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Communications in Analysis and Geometry
Volume 25 (2017)
Number 3
A strong Harnack inequality for graphs
Pages: 557 – 588
DOI: https://dx.doi.org/10.4310/CAG.2017.v25.n3.a3
Authors
Abstract
We introduce the curvature (and the flow curvature) for graphs, which allow us to prove several Harnack inequalities for general graphs (which are not necessarily regular). We first show that for a graph with curvature $\kappa$, the combinatorial eigenfunction $f$ associated with eigenvalue $\lambda$ satisfies, for any edge $\lbrace x, y \rbrace$,\[{\lvert f(x) - f(y) \rvert}^2 \leq (8 \lambda + 4 \kappa) d_{max}\]where $\max_x \lvert f(x) \rvert = \max_x f(x) = 1$ and $d_{max}$ denotes the maximum degree. The above inequality is used to prove a a strengthened inequality which implies that the ‘stretches’ of edges determined by eigenfunctions are particularly ‘small’ (in terms of the associated eigenvalue and curvature) near the maximum point. Namely, for a graph with curvature $\kappa$, the combinatorial eigenfunction $f$ associated with eigenvalue $\lambda$ satisfies, for any edge $\lbrace x, y \rbrace$,\[{\lvert f(x) - f(y) \rvert}^2 \leq \frac{c_1 \lambda + c_2 \kappa}{\beta - 1} (\beta - f(x))^2\]where $c_5 \geq \beta \geq 1 + c_3 \lambda + c_4 \kappa$ and $c$’s are constants depending only on the maximum degree of the graph.
Received 19 February 2015
Published 13 September 2017